0=3z^2-27

Solution for 0=3z^2-27 equation:

0=3z^2-27

We move all terms to the left:

0-(3z^2-27)=0

We add all the numbers together, and all the variables

-(3z^2-27)=0

We get rid of parentheses

-3z^2+27=0

a = -3; b = 0; c = +27;
Δ = b2-4ac
Δ = 02-4·(-3)·27
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18}{2*-3}=\frac{-18}{-6}
=+3
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18}{2*-3}=\frac{18}{-6}
=-3
$